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- Placerville, CA, USA
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- Retired PV System Designer
But the difference in voltage at the load will not directly tell you the difference in VD, since there are vectors involved.
A highly inductive supply (just out a real inductor in for example) can cause a large voltage drop to the load without dissipating much power at all. A perfect inductor would have no I^2R loss.
Looking at first order effects, you do not care about the resulting load voltage, only about the resistive component of the VD.
Tapatalk!
A highly inductive supply (just out a real inductor in for example) can cause a large voltage drop to the load without dissipating much power at all. A perfect inductor would have no I^2R loss.
Looking at first order effects, you do not care about the resulting load voltage, only about the resistive component of the VD.
Tapatalk!
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