petersonra
Senior Member
- Location
- Northern illinois
- Occupation
- engineer
Why not just put VFDs on all your motors? In a lot of cases a VFD is not a lot more than the PFC capacitors.
This is a 225kW/300hp motor. A VFD would have been a much more expensive option not to mention the harmonics issues.Why not just put VFDs on all your motors? In a lot of cases a VFD is not a lot more than the PFC capacitors.
the OP seemed to be talking about PFC in general and not for a specific size motor.
I don't often deal with anything much below about 30kW and that would be much more expensive than PFC.In a lot of cases a VFD is not a lot more than the PFC capacitors.
I have often had this vision of every motor on the grid being on a VFD and the current waveforms causing the utility lines to dance.![]()
Not for many cases but the net adds up for some cases (large poor pf loads located a long way from the meter that run a lot of the time).But that's usually not a lot.
He did not say solely as we know there are other charges. But as for billing on kVA, some do. Here is just one example: http://www.cityofames.org/index.aspx?page=113OK, no. First off I have NEVER seen a utility that bills solely on kVA demand. They bill on kWh, then in SOME cases there is a PENALTY for exceeding an allotted kVA demand. But they do not "bill on" kVA demand.
I agree they are small but can make the installation worthwhile in some cases (see response to Bes).Secondly, "marked savings" is the kind of nebulous fluff terminology you see in a marketing pitch, I differ with what it implies.Hmmm... I'd say that value is debatable. If the conductors are properly sized to code requirements and adjusted for voltage drop under full load, then the losses would be very low to start with. I believe that 1-2% would be a stretch.
You would be right for many cases but not all.That would be your first purely true statement. The reason they are not installed to reduce kW is because... doing so doesn't save enough kWh to make it worth doing!
Maybe. Run the numbers then get back to me.Do they exist? Yes. Are they worth the cost of installing PFC capacitors JUST for the purpose of attaining that miniscule reduction in losses? No.
That may be interesting. I'll have to think about.But if the fault level is low, there may be considerable saving in installing capacitor at equipment.
Seems like you forgot reactance.Take as an example, a low power factor load that uses 100 amps single phase, with voltage drop in the wires of 6 volts. The losses are clearly 600 watts.
It is just another way to bill for kW and poor power factor.1. Billing per KVA for the highest 15 minute KVA recorded during the billing cycle seems pretty close to the concept of a penalty for high KVA, just without the step function at some minimum level.
Me neither. I have seen the use of kWh and kvarh to calculate the average kVA for billing purposes.2 "Billing for KVA" is not to be confused with billing per KVAH, which I do not know of any POCO doing.
Most utilities do it that way for demand rates.Is anybody aware of a utility that bills based on highest KW as well as on cumulative KWH?
Most utilities do it that way for demand rates.
Your units are mis-matching so your question is not clear.I was specifically asking about billing based on highest kWh only rather than folding kWh and KVAR together into one KVA charge.
Not sure about that.The OP wants a criterion to ascertain whether there is any KW saving by installing load side capacitor in an electrical installation. The formula for reduction in voltage drop in post #17 may well serve as the criterion. For example if 10 MVA is the fault level and 0.7 MVA is the PFC capacitor size, then applying the formula, the reduction in voltage drop =(0.7/10)*100=7%. So the power saving may be up to 7%, worth a try to do further calculations to confirm it. But if the fault level is 100 MVA instead of 10 MVA, then the reduction in voltage drop is =0.7% only. So there would be no power saving in this case.
Your solution to use the same transformer to power the low power factor induction motor by connecting PFC capacitor after its starter would create problems for the motor and other connected loads if the corrected pf is more than 0.95.SeeI've seen it done, and done it myself for two main reasons.
It reduces maximum demand in terms of reduced kVA. Exceeding maximum demand is extremely costly in this country.
The other application is reducing the size of conductors and/or supply capacity. We currently have an installation for pumps where the customer decided to change the motor from a synchronous induction motor with unity power factor to cage induction motors with 0.76 p.f. One serious consequence of this was that the unit transformer supplying the original motor was not rated for the increased kVA. PFC fixed this by getting the pf up to about 0.97.
Energy saving? Not really. As is our usual practice, we fitted detuning chokes and the losses in these, though not a lot, was about the same as the reduction cable losses resulting from the reduced current.
Perhaps not, because for cable size up to 35 sq.mm, approximately,70 Kcm, the reactance may be ignored and only resistance of cable may be taken into account.Seems like you forgot reactance.
Voltage drop is a function of magnitudes, not vectors. I've discussed this before in another thread somewhere.Perhaps not, because for cable size up to 35 sq.mm, approximately,70 Kcm, the reactance may be ignored and only resistance of cable may be taken into account.
The goal for the OP is to ascertain power saving irrespective of system voltage. If the lines are of predominantly resistive in comparison to its inductive component i.e its inductive can be ignored, then it is easy to see that percentage reduction in voltage drop is the same as the percentage reduction in power loss i.e percent KW saving ( it can be derived from the formula in post#17).Not sure about that.
With a 480 volt scenario similar to my prior post we have about a 1.5% volt drop with few tenths of percent change in the volt drop and about a 10-15 year simple payback, depending on parameters.
For a higher volt drop, say using 240 volts, we are in the 3% volt drop range with about a 1/2 percent volt drop change but the payback goes to 5-10 years, depending on parameters.
So, the higher the volt drop, the more the opportunity for a faster payback even if the % change in volt drop is not several percent.
But still supply lines reactance plays a part in the load end voltage magnitude, if it can not be ignored.Voltage drop is a function of magnitudes, not vectors. .
I don't think it is a very good article. The very notion that the PFC would be connected downstream of the motor overload is not something I would expect any half competent engineer to do.And on making the capacitor smaller if the motor is not running at FLC is a bit odd as well. Draw out the Steinmetz equivalent circuit and you may begin to understand.Your solution to use the same transformer to power the low power factor induction motor by connecting PFC capacitor after its starter would create problems for the motor and other connected loads if the corrected pf is more than 0.95.See
http://ecmweb.com/power-quality/basics-pf-correction-single-induction-motors
But if the connection of the capacitor is before the starter i.e if the capacitor has a separate ON-OFF control, there is no problem:you could correct the pf up to unity.