Rick,

Thank you for being cordial. I was just adressing post 130:

Rick said: "there must be a voltage drop across the wire for current to flow through the wire"

David said: "Rick, you truly surprise me. If this statement was true then Ohm's law would not work in an ideal case. Consider a circuit with a 12V battery with terminals + and -. From + we run an ideal conductor (with no impedance) to a 12 ohm resistor (terminal R1.) On the other end of the resistor (terminal R2) we route an ideal conductor to the battery terminal -. According to Ohm's law I=V/R, there will be a 1 Amp current flowing through the circuit. However, if we isolate the conductor from terminals + to R1, it is plain to see that there is no voltage drop from + to R1, yet there is clearly 1 Amp flowing along this conductor. From your statement above, this could not be happening, so Ohm's law must be wrong. Let me correct your statement - it should say "there must be a current flow through a wire for there to be a voltage drop across it."

That is what I am addressing, and it seems pertinent to what the discussion has evolved into. If this line of thought needs to be moved, perhaps a Moderator would be kind enough to split the thread.

I firmly believe the statement you made. David said if it were true, then ohm's law must fail under extreme conditions. I am attempting to show that ohm's law does indeed fail under extreme conditions.