:?
480 is another calculation and system all on its own.
Let us manually compute for them then:
For the single phase 240v at 0 feet result above (infinite bus assumption) = 15621amp,
computing using the short cut method
75,000/240/0.02=15625
or the long cut method
kVa = 75,000
voltage =240v
The impedance of a load that would draw 75 kVA is 240^2/75000 = 0.768 ohms.
Transformer impedance = 0.02x 0.768 = 0.01536
Short circuit current = 240v/0.01536 = 15625
For the 3 phase
The table value is 13,528 for 480v
using infinite bus assumption short cut... sqrt(3)*75000/480/0.02= 13531 amp
at 240v = 13531 x (480/240) = 27063v
at 208v = 13531 x (480/208) = 31226v
which matched the above.
But I don't know the exact formula for getting impedance of wires. Any ideas?
What should be done is simply adding the impedance of the transformers and wires, then divide the voltage with the impedances to get the panel short circuit current. I want to manually compute everything and put in excel spreadsheet just to verify everything.
This is to make sure I get accurate results in getting the panel bolted short circuit current at office and residential (this is because I was alarmed and surprised today the arc flash potential at home is greater.. in case the main breaker fails to open. Remember IEEE 1584-2018 has now 2kA arcable threshold instead of 87kA).