- Location
- Windsor, CO NEC: 2017
- Occupation
- Service Manager
Is this right?
View attachment 7752
Seems to me that the voltmeter on the power supply should be reading 120V, not .8V. Is there something I'm missing here? :?
Nowhere.Where would I connect a voltmeter to find that reading though?
Is this right?
View attachment 7752
Seems to me that the voltmeter on the power supply should be reading 120V, not .8V. Is there something I'm missing here? :?
The graphical representation is badly made for what it attempts to illustrate. The voltage readings around the circuit should be taken from point to point around the circuit and the sum of the individual voltage readings around the circuit should add up to the voltage that is read at the source terminals, so the voltage across the source terminals should be 119.2V instead of 0.8V. (Is this drawing saying that it is completely safe to touch the outgoing terminals of a loaded circuit at 0.8V? My practical experience says otherwise. ) It is based on Kirchhoff's Second Law. The showing of the 16A in two places is unnecessary. Kirchhoff's First Law.Is this right?
View attachment 7752
Seems to me that the voltmeter on the power supply should be reading 120V, not .8V. Is there something I'm missing here? :?
The volt meter should reflect the loss across the resistance of the power supply as it should read 119.2v which is the circuit supplied voltage, not 120v.
...and the sum of the individual voltage readings around the circuit should add up to the voltage that is read at the source terminals...
No. It is making a bad situation worse because it introduces even more technically incorrect information.that .8V is lost getting to the very center of the secondary. Essentially, the ends of the conductor extend internally into the transformer to the center of the winding.
Would y'all buy that?
No. But here is what I would buy- "What you need to know to get you through the day in the real world is that amps are the same any where in a circuit. Keep pestering me about the flaw in this illustration and I am going to get a physics professor and a EE in here. By the time they are done with you, you won't know which way to open a door to get out of a room. AND there will be a test. Flunk it and you won't get any PDU's"My official position is that the loss is real, but is essentially seen as a loss due to transformer inefficiency. Since the secondary is constructed of wire that has resistance, that .8V is lost getting to the very center of the secondary. Essentially, the ends of the conductor extend internally into the transformer to the center of the winding.
Would y'all buy that?
No PDU's for you.amps are the same any where in a {series} circuit.
:weeping: I'm a broken man. Yet I don't blame myself, but rather society.No PDU's for you.
Me too.:weeping: I'm a broken man. Yet I don't blame myself, but rather society.