Phil Corso
Senior Member
- Location
- Boca Raton, Fl, USA
VA is not a measure of power. Nor is VAr. And watt = va is just nonsense. And I don't soak bees.
Besoeker, did I not start this topic with the same premise?
More later!
Phil
VA is not a measure of power. Nor is VAr. And watt = va is just nonsense. And I don't soak bees.
Power is power. VA and VAr are not.
I don't know why I bother......
yep, the amps differential i mention is used to create that heat you speak of and needs to be accounted for in the prime mover.I like the 'time average' bit showing what goes back and forth from poco to the inductive load has 0 average power, thus it is imaginary power, but along the way it sure makes my wires warmer - I think?
It isn't power. Power is expressed in Watts.
It isn't Watts.
I don't which part of that you don't get.
Being imaginary power makes it not real... just like anything else imagined. :happyyes:Isn't power.
VA is not a measure of power.
Nor is VAr.
And watt = va is just nonsense.
And I don't soak bees.
Being imaginary power makes it not real... just like anything else imagined. :happyyes:
So, if as a child you had an imaginary friend, would you now say he/she/it is not a friend...? :angel:
Being imaginary power makes it not real... just like anything else imagined. :happyyes:
So, if as a child you had an imaginary friend, would you now say he/she/it is not a friend...? :angel:
if this doesn't do it I'm out of ideas lol :lol:
If there is no power in reactive va, then why does the wire it runs thru get warm due to I^2R losses from it? If it has no power, then we would not have to concern ourselves with transmission line losses, no?
I like the 'time average' bit showing what goes back and forth from poco to the inductive load has 0 average power, thus it is imaginary power, but along the way it sure makes my wires warmer - I think?
There is no need for an analogy. Power is Watts. It really is that simple.i tried to explain with my steam piston analogy a few pages back.
There is no need for an analogy. Power is Watts. It really is that simple.
I don't know why such a Fandango is being made out of it.
There is no need for an analogy. Power is Watts. It really is that simple.
I don't know why such a Fandango is being made out of it.
There is no need for an analogy. Power is Watts. It really is that simple.
I don't know why such a Fandango is being made out of it.
Because of the R term which is not a reactive component.Then how does the reactive power cause I^2R losses in the feedline?
Because of the R term which is not a reactive component.
watt = joule/sec = v x a = joule/coulomb x coulomb/sec = joule/sec = watt = va