mivey
Senior Member
Why do you ask? There are many ways. A phase angle meter would be one way.How will you measure it?
Why do you ask? There are many ways. A phase angle meter would be one way.How will you measure it?
With a phase angle meter,measure phase angle differences for all loads connected across 120v/240v supply in a typical home,say yours,taking two voltages across two loads at a time.You will find zero phase angle phase difference in all cases.What does it mean?Why do you ask? There are many ways. A phase angle meter would be one way.
Then how do you think Lissajous figures for 0 degree phase difference and 180 degree phase difference for two sine waves are obtained?If you take a single supply of just 120V it is just a single supply of 120V, Reversing how you measure it doesn't reverse its phasing.
Easy enough.With a phase angle meter,measure phase angle differences for all loads connected across 120v/240v supply in a typical home,say yours,taking two voltages across two loads at a time.
No, you will not.You will find zero phase angle phase difference in all cases.
Not real sure if you are asking a real or rhetorical question but:What does it mean?
First you please check the continuity between the grounds of two probes connected to the scope in the X-Y mode.Does the continuity exist?
I'm not sure where you are going but there is a difference in having one voltage and having two voltages.Then how do you think Lissajous figures for 0 degree phase difference and 180 degree phase difference for two sine waves are obtained?
Please provide solid evidence.No, you will not.
Because you miss the obvious such as in a 120V/240V supply all load voltages in a home are in phase and so the 120V/240V supply to a home is called single phase supply and like that.Not real sure why you just do not state what you have to say instead of asking questions with obvious answers. Why ask questions like this?:
Any number of prior posts have already done that. But excluding the phases of the currents, and excluding the phase shift due to source impedance differences, at the very least you have this in post #847.Please provide solid evidence.
That's what we are debating. I say the view of some of them being "in phase" is muddied by definitions and preferences.Because you miss the obvious such as in a 120V/240V supply all load voltages in a home are in phase
It is called that because the loads are normally all single-phase and the transformer is a single-phase transformer.and so the 120V/240V supply to a home is called single phase supply and like that.
I requested you for a solid evidence such as two loads in a home,one fed by 120V voltage and another by -120V voltage.You need to find it through your phase angle meter in your hand and identify that two loads.But you are presenting me with some imaginary construct.What is the problem?Any number of prior posts have already done that. But excluding the phases of the currents, and excluding the phase shift due to source impedance differences, at the very least you have this in post #847.
To put an end to your debate,I requested you to ascertain the phase difference across all loads in a home using a suitable meter such as a phase angle meter.That's what we are debating. I say the view of some of them being "in phase" is muddied by definitions and preferences.
But it equates to all single phase load voltages in 120V/240V supply are in phase as can be readily measured by a phase angle meter,for example."All loads are single-phase" does not necessarily equate to "All loads are in phase"
Take an oscilloscope in X-Y mode and with the individual grounds of its each probe separated in the scope i.e its two sets of deflector plates are separate.Apply 120v single phase supply to X-Y plates through two sets of leads.You may get a Lissajous figure in the scope.Reversing any two leads connected to X or Y plates will change the Lissajous figure in the scope.Won't it?I'm not sure where you are going but there is a difference in having one voltage and having two voltages.
A two-wire circuit can only be a single-phase circuit. To have more than one phase, you need more than two wires (i.e. you need more than one voltage or current).
Don't use a scope very often, do you?Take an oscilloscope in X-Y mode and with the individual grounds of its each probe separated in the scope i.e its two sets of deflector plates are separate.
That's equivalent to taking a 1.5V battery and measuring the voltage across it, first with the red lead connected to the positive then with the black lead connected to the positive then concluding that the humble C cell has two different voltages because the meter gave you two different readings. It's nonsense.Apply 120v single phase supply to X-Y plates through two sets of leads.You may get a Lissajous figure in the scope.Reversing any two leads connected to X or Y plates will change the Lissajous figure in the scope.Won't it?
With due respect,you do not understand the difference between a DC voltage and AC voltage.That's equivalent to taking a 1.5V battery and measuring the voltage across it, first with the red lead connected to the positive then with the black lead connected to the positive then concluding that the humble C cell has two different voltages because the meter gave you two different readings. It's nonsense.
Then I couldn't possibly know how to make controlled rectifiers at 40,000Adc configured as 24-pulse systems.With due respect,you do not understand the difference between a DC voltage and AC voltage.
Here's one from a site where we are currently undertaking an upgrade.
Its days are numbered.....
Here is an idea: How about you do your own lab work? I want you to build what I have show in my graphic and prove that it is not so. Hop to it Cassidy.I requested you for a solid evidence such as two loads in a home,one fed by 120V voltage and another by -120V voltage.You need to find it through your phase angle meter in your hand and identify that two loads.But you are presenting me with some imaginary construct.What is the problem?
I have done so countless times. since you have a tendancy to not believe what other people measure, I want you to do your own lab work.To put an end to your debate,I requested you to ascertain the phase difference across all loads in a home using a suitable meter such as a phase angle meter.
Had you been able to follow what I posted, you would see that you can measure voltages with a 0? displacement and you can also measure voltages with a 180? displacement. Get to your lab now and find out for yourself.But it equates to all single phase load voltages in 120V/240V supply are in phase as can be readily measured by a phase angle meter,for example.
Why don't you do your own lab work and let us know how this works out for you.Take an oscilloscope in X-Y mode and with the individual grounds of its each probe separated in the scope i.e its two sets of deflector plates are separate.Apply 120v single phase supply to X-Y plates through two sets of leads.You may get a Lissajous figure in the scope.Reversing any two leads connected to X or Y plates will change the Lissajous figure in the scope.Won't it?
:roll:With due respect,you do not understand the difference between a DC voltage and AC voltage.
Here's one from a site where we are currently undertaking an upgrade.
Its days are numbered.....
There is certainly resistance to saying that two voltages can have a real physical 180? phase displacement when present across two series windings.
The "maximum positve value" is the sticking point.
Viewed from the right side of my graphic, that reference frame would say that the positive peaks of both waveforms occur in the same direction at the same time. Their negatives work in synch in the opposite direction 180? later.
Viewed from the left side of my graphic, that reference frame says the positive peak of one waveform is working in synch with the negative peak of the second waveform. They also work together in the opposite manner at a point 180? later.
As my graphic shows, the voltages map to the same physical space and the only thing that makes a difference is the reference frame we choose. Both reference frames are valid and both voltage sets actually exist as can be seen by the voltages across the load in my graphic.
Everything we are discussing is about how they appear.Again nothing but how they appear based on how they are measured.
Do you take issue with the model I have in my graphic? Are you saying this it is not a physically-realizable model?You are still discussing models not the real world.
Never said it was.Physically connecting two windings, on a common core, in a X1->X2+X3->x4 series arrangement is not the same as physically connecting them in a X1->X2+X4->X3 arrangement.
Never said it was.Physically connecting them in a X1+X3->X2+X4 parallel arrangement is not same as a X1+X4->X2+X3 arrangement.
The oscilloscope pictures I posted were real world pictures.You are still discussing models not the real world.
Physically connecting two windings, on a common core, in a X1->X2+X3->x4 series arrangement is not the same as physically connecting them in a X1->X2+X4->X3 arrangement.
Physically connecting them in a X1+X3->X2+X4 parallel arrangement is not same as a X1+X4->X2+X3 arrangement.
And straight from the Ark.State of the art!