First, a winding alone has no phase. It is the waveform in the winding which exhibits a phase. Even so, I have no disagreement with the general statement that the "windings are in phase" if they can be paralleled without the fireworks. What we mean is that the voltages are in phase. Let's call that an absolute based on the physical.Was not trying to be a complete pest. I just wanted common ground on the fact it is possible to have an absolute answer based on the physical construction of a transformer.
Mivey seems to disagree
Well you can certainly remove it. But once you remove it you no longer have the same two functions and would need to replace "=" with "≠", at least in our world.I think we have enough defintions by now, but I still don't understand how one can remove a negative sign from an equation such as,
sin(wt + 180) = -sin(wt)
Can anyone explain it to me?
You mean V12=V1n+Vn1 at any instant is wrong?No. V2n is the load voltage not Vn2, and we measure the "difference in potential" between L1 and L2. We can do this with instantaneous values or with phasors. We cannot do it with RMS values.
Yes.It is my humble opinion that because of your that misunderstanding,you do not admit that 120/240v supply is a single phase supply!Let me get this right.
You want to check my understanding of the differences between AC and DC?
Is that what you mean?
Possibly, but only if you accept trigomometric identities are real - they appear to be beyond mivey's comprehension.I think we have enough defintions by now, but I still don't understand how one can remove a negative sign from an equation such as,
sin(wt + 180) = -sin(wt)
Can anyone explain it to me?
Feel like a bigger man now?Possibly, but only if you accept trigomometric identities are real - they appear to be beyond mivey's comprehension.
Wow what a shock X<>-X....another real-world fact also exists and that fact is that X1-X2 is not in phase with X4-X3.
Possibly, but only if you accept trigomometric identities are real - they appear to be beyond mivey's comprehension.
Do you accept trig identities as valid?Doesn't really answer the question. Question was not about trig. I learned in HS that you can manipulate both sides of an equation equally, but I didn't learn that you could invert only one side. How do you do it?
All those math courses, wasted!
Do you accept trig identities as valid?
And the shocking lesson that there is more than one truth. So I guess since it really is that simple then you would agree that we have these two physical truths:Wow what a shock X<>-X.
So what?And the shocking lesson that there is more than one truth. So I guess since it really is that simple then you would agree that we have these two physical truths:
1) The voltage from X1 to X2 and the voltage from X3 to X4 have a 0? displacement between them
2) The voltage from X2 to X1 and the voltage from X3 to X4 have a 180? displacement between them
You mean V12=V1n+Vn1 at any instant is wrong?
So it is a physical fact, not just a mathematical equivalent, that we have 0? voltages and 180? voltages across the windings. The difference is which reference frame you use, but both are physical realities.So what?
The solution is beyond the scope of high school algebra. However, if you remember back far enough you should remember that for simple equations only one side of the equation should be manipulated properly. Manipulating both sides was a "short-cut" until you resolve (or isolate) the final variable. But the principal you mentioned was still valid.The question was about algebra, not trig.
I'm kind of confused why you are asking this. It is actually the founding basis for your argument. This is the mathematical principle that permits you to take a physical inversion and turn it into a mathematical phase shift. If you reject this mathematical equality, then you can't even claim that you have an "apparent" phase shift, let alone a "real" one.I think we have enough defintions by now, but I still don't understand how one can remove a negative sign from an equation such as,
sin(wt + 180) = -sin(wt)
Can anyone explain it to me?
So it is a physical fact, not just a mathematical equivalent, that we have 0? voltages and 180? voltages across the windings. The difference is which reference frame you use, but both are physical realities.
In other words, we have both in-phase voltages and phase-opposed voltages at the transformer.
But it is not unique:if 120/240v supply has it,120V supply also does.Correct?So it is a physical fact, not just a mathematical equivalent, that we have 0? voltages and 180? voltages across the windings. The difference is which reference frame you use, but both are physical realities.
In other words, we have both in-phase voltages and phase-opposed voltages at the transformer.