wwhitney
Senior Member
- Location
- Berkeley, CA
- Occupation
- Retired
I agree with your point about the bus stabs, although I would be surprised if that were a significant factor in the overall bus heating. But I'm going to disagree with the above.Instead, each phase current Ip also has a vector component Ipq that's at 90 degrees from Ipi, and with a magnitude sin(30) x Ip = 0.5 Ip. This current flows between the two phases at a delta connection. And although it does not appear in the line output, this current Ipq goes through the buss when the delta is constructed by connecting backfed breakers to the bus.
Say the A bus is an idealized line, and it has just 3 connections, in order: (1) a 2 pole breaker on AB phases, (2) a 2 pole breaker on AC phases, and (3) the 3 pole main breaker. With 3 single phase inverters connected in a delta arrangement, say with an output of 60A, the current on the segment 1-2 will be 60A, and the current on segment 2-3 will be 60 sqrt(3), not 120. The current Ipq you are talking about does not flow through the bus.
Remember, these vectors are just short hand for waveforms, and if you add the actual waveforms, you will see that the current does not exceed 100 sqrt(3) on the bus. Of course, I don't know anything about the 3D effects of an actual bus, but again I would be surprised if that variation from the idealized model caused significant heating.
Cheers, Wayne