My first instinct was to integrate the area of the cube over the length between the two corners and multily that by the resistivity. With some very rusty calculus, I came up with:How about the resistance between opposite corners of a solid cube of copper?
I am gonna have trouble soldering that.Originally posted by physis:
Using calculus gives you one atom of contact.
Ha Ha.
Class C Mil-Spec buddy, class C Mil-Spec.By Iwire:
I am gonna have trouble soldering that.
I'm just starting to understand calculus, but I get the impression sometimes that it's a mathematical gimmick that, instead of representing reality, is sort of a mathematical band-aid that forces the numbers to do something.By Steve:
In calculus, there is a particular funnel shape (I forgot what it is called). As you go from the open end toward the point, it tapers in a paticular way that it takes it forever to get to a point. So the funnel has an infinite surface area, but it has a finite volume because of the way it tapers.
If you try to paint the inside with a brush, it would take an infinite amount of paint (because of the infinite surface area). But in theory, you can paint it very easily just by pouring the paint in.
The thing that "calculus" misses is the thickness of the atoms or molecules that you mentioned. That's what made me think of it.Is the funnel shape real?
I guess nobody has explained atoms or molecules to the math majors They kind of live in their own little world.Wouldn't that make the derivative you're using "untrue"?
The corners have area = 0, but only for a length =0. If we plug this into your equation, we get:R = rho x length/area.
where R is in Ohms, rho is in Ohm-cm, length is in cm, and area is in square cm.