Resistance Cube

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Re: Resistance Cube

So is getting nitrogen from it's gas state to liquid. :p

Edit:Error A

[ June 13, 2005, 12:51 PM: Message edited by: physis ]
 
Re: Resistance Cube

By Rattus:

How about the resistance between opposite corners of a solid cube of copper?
My first instinct was to integrate the area of the cube over the length between the two corners and multily that by the resistivity. With some very rusty calculus, I came up with:

R = sqrt(3)*Rho*L^6

if Rho is the resistance per unit volume and L is the length of one side of the cube.

But one thing is nagging me. A perfect cube would have zero area right at the corner. Nothing to attach the wire to. Same with a sphere. So I keep wondering if the correct answer is R = 0.

Steve
 
Re: Resistance Cube

Originally posted by physis:
Using calculus gives you one atom of contact. :D :D :D

Ha Ha.
I am gonna have trouble soldering that. :D

[ June 13, 2005, 05:19 PM: Message edited by: iwire ]
 
Re: Resistance Cube

In calculus, there is a particular funnel shape (I forgot what it is called). As you go from the open end toward the point, it tapers in a paticular way that it takes it forever to get to a point. So the funnel has an infinite surface area, but it has a finite volume because of the way it tapers.

If you try to paint the inside with a brush, it would take an infinite amount of paint (because of the infinite surface area). But in theory, you can paint it very easily just by pouring the paint in.

Steve

[ June 13, 2005, 05:23 PM: Message edited by: steve66 ]
 
Re: Resistance Cube

By Iwire:

I am gonna have trouble soldering that. :D
Class C Mil-Spec buddy, class C Mil-Spec. :D

[ June 13, 2005, 05:24 PM: Message edited by: physis ]
 
Re: Resistance Cube

By Steve:

In calculus, there is a particular funnel shape (I forgot what it is called). As you go from the open end toward the point, it tapers in a paticular way that it takes it forever to get to a point. So the funnel has an infinite surface area, but it has a finite volume because of the way it tapers.

If you try to paint the inside with a brush, it would take an infinite amount of paint (because of the infinite surface area). But in theory, you can paint it very easily just by pouring the paint in.
I'm just starting to understand calculus, but I get the impression sometimes that it's a mathematical gimmick that, instead of representing reality, is sort of a mathematical band-aid that forces the numbers to do something.

I know it can provide real solutions too. It just seems like with calculus you "tell it what to say".

Edit: is the funnel shape real?

[ June 13, 2005, 05:54 PM: Message edited by: physis ]
 
Re: Resistance Cube

Is the funnel shape real?
The thing that "calculus" misses is the thickness of the atoms or molecules that you mentioned. That's what made me think of it.

Pretty soon the funnel tapers to a single molecule. So the funnel can't really follow the gradual, infinite taper down to zero area. And the paint comes in "molecule lumps" which is also ignored. So I guess its more of a mind exercise than something real.

Steve
 
Re: Resistance Cube

Wouldn't that make the derivative you're using "untrue"?

Edit: Error A, I can't spell derivitave. Sorry Steve. :D

[ June 13, 2005, 08:59 PM: Message edited by: physis ]
 
Re: Resistance Cube

Since we are assuming a perfect cube, the area of contact at each corner is infinitely small, therefore, the conductance of the contact is infinitely small, zero that is.

G = 0

R = infinity.

Don't sweat the small stuff like the size of the atoms.
 
Re: Resistance Cube

Posted by Sam:

Wouldn't that make the derivative you're using "untrue"?
I guess nobody has explained atoms or molecules to the math majors :D They kind of live in their own little world.

Steve
 
Re: Resistance Cube

Rattus:

So my hunch about the conductance being zero was correct. But you still have one thing left to explain. I'm stealing the following from one of your posts to another thread:

R = rho x length/area.

where R is in Ohms, rho is in Ohm-cm, length is in cm, and area is in square cm.
The corners have area = 0, but only for a length =0. If we plug this into your equation, we get:

R= rho x 0/0. This is called an indeterminate form. Can you prove it really is infinity??

Steve

[ June 14, 2005, 09:18 AM: Message edited by: steve66 ]
 
Re: Resistance Cube

I don't have any calculations Rattus. I haven't got the inclination to go after it yet. Maybe in a few days.
 
Re: Resistance Cube

Steve,

You cannot apply the resistance formula directly for the reason you note. You have to sneak up on it.

Let us arrange the cube such that one corner lies at the origin of the xyz plane, and the opposite corner lies on the positive x axis.

Now let delta(x) lie between 0 and x on the positive x-axis.

Then delta(R) = k*delta(x)/delta(x)^2 = k/delta(x)

Take the limit of this expression as delta(x) goes to zero, and ZOWIE!, we find that delta(R) goes to infinity.

You can also write a differential equation:

dR = k*x^-2*dx,

where x lies within the 3-sided pyramid with its tip at the origin; then,

R = -k*x^-2 evaluated between 0 and x which leads to,

k/0 - k/x = infinity.

QED
 
Re: Resistance Cube

That works. Or you could also apply L'Hopital's rule to R = Rho * length/area and get 1/x which also shows the resistance goes to infinity.

Steve
 
Re: Resistance Cube

This is hardly electrical but I can't help posting some observations being that this thread is headed into calculus. I'll get to resistance too though.

I stumbled across this thing called Gabriel's Horn Steve. I did'nt make this. I'll post a link if anyone wants it.

:D You ought to change your limit to the dimension of a copper atom and see what the resistance of copper is. :cool:
 
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