let me ask another Q.
60Hz, if i have some pure R elements, I(t)=V(t)/ΣR , yes?
and the power dissipated by any R element is I(t)2Relement = real watts = power
Yes to the above, with the elaboration that R is a real number.
now i have real inductor, an R value and a XL value, R+XL = Z
Well, if you want X
L to be real, then you need to write R + jX
L = Z, where Z is complex. I forget whether X
L is positive or negative from this point of view.
Or you could just let X
L be purely imaginary, then your equation works as you've written it. I don't know what the usual convention is.
Yes, with reservations. Certainly in magnitude I = V / |Z|.
To represent the phase shift, my understanding is that the usual method is to say that V(t) = Re V
0e
jωt, where Re means take the real part, V
0 may be complex, and ω = 60*(2π) for 60 Hz power. Similarly I(t) = Re I
0e
jωt.
With the above conventions, then I
0 = V
0/Z as complex numbers.
and the power dissipated by R is I(t)2R = real watts = power(t)
Yes.
the Q is I(t)2XL = not consumed watts = no power(t)
Q is reactive power, and I don't know that it makes sense to consider it instantaneously.
Cheers, Wayne