See how easy:
See how easy:
mivey said:
One of the unresolved issue:
Is this what you had in mind?
V1n = 120 @0
V2n = 120 @180
V12 = 240 @0 {V1n - V2n = 120@0 - 120@180}
V21 = 240 @180 {V2n - V1n = 120@180 - 120@0}
I4 = 240/R4 @180 {V21/R4 = 240@180/R4}
I3 = 240/R3 @0 {V12/R3 = 240@0/R3}
I1 = 120/R1 @0 {V1n/R1 = 120@0/R1}
I2 = 120/R2 @180 {V2n/R2 = 120@180/R2}
Now, let us assign the value of 10 Ohms to each resistor, then,
I1 = 12A @ 0
I2 = 12A @ 180
I3 = 24A @ 0
I4 = 24A @ 180
Then,
In = I1 + I2 = 12 @ 0 + 12 @ 180 = 0
The direction of In is determined by the direction of the larger current.
Then the source current is,
I12 = I1 + I3 - I4 = 12 @ 0 + 24 @ 0 - 24 @ 180 = 60 A @ 0
Do not confuse I1 with 11, etc.
Now anyone can work this with any R values they wish.