- Location
- Massachusetts
Do you know pump affinity laws? Have you checked your statement with them?
Why not post what 'affinity law' you feel I have broken?
Do you know pump affinity laws? Have you checked your statement with them?
That's line voltage, not motor voltage.Please look again at tables.The current in save mode is less but the voltage more;the current in the bypass mode is more but the voltage is less.This is what I am asserting.
Hi GarI just need a real device marketed for for the scam so that no one can claim that what I used for the test was somehow different from what is being sold.
Yes, very good point.111116-1541 EST
Besoeker:
I think your analysis is likely a big factor.
I am also thinking that since the light bulb transition is underway and that homeowners are buying new appliances that this may contribute to a 6% reduction in addition to what you are suggesting.
Not sure where you were going with this.Some of my ancestors are from England. If we can make a connection in one path around the late 1700s, then this path leads to a person in about 1050. After about 1300 it is surprising how many individuals lived into their 80s or 90s.
111116-1411 EST
Instead of trying to refine my experiment with the capacitors I used in post #1 I have now ordered one of the commercial units claiming big power savings.
I did not want to disclose much information so my questions were limited.
The company I ordered from has a current special price of essentially $100 including shipping. This apparently results from another company advertizing a similar price.
This company, KVAR, has two residential models. One is a -1050 and the other -1200. I asked what was the difference since both have the same price. The answer was a different amount of capacitance. This makes no sense to price them the same. Then I ask what was the capacitance? The answer --- proprietary. What nonsense. Any competitor would have no problem determining what was in the box.
How they determine which unit is correct for you is based on the size of your electric bill. $170 is the transition point. Since I do run $200 a month on rare occasions I gave them that figure to convince them I should get the higher capacitance unit. My guess is this will have two 40 ufd capacitors.
They seem to guarantee you a 6% saving. I have to see what the fine print says when I get the unit. I have no plans to confront them with proof of what it does. It is a useful capacitor to have sitting around for whatever I might do with it.
You rock.
10-4 on that. Gar, you da man. :thumbsup:
I want toys these EEs get.
Best I can do is that Santa says I may get a Fluke T-179 for Xmas.
Trolling means deceiving.If you think I posted false information with an intention to deceive,you may list them for all others to see.
Oh no! Now you are breaking laws and physics! What is the world coming to?Why not post what 'affinity law' you feel I have broken?
Aren't they limited to a constant efficiency assumption or something like that (I do not feel like looking it up)?Do you know pump affinity laws? Have you checked your statement with them?
You are correct.It is line voltage not motor voltage.But the current is also line current and not motor current.Unfortunately,motor voltages and motor currents were not displayed.That's line voltage, not motor voltage.
Look again at the title.
Reduced Motor Voltage.....
Bit of a clue there, don't you think?
You would expect the voltage to be marginally higher is save mode because the current is is less resulting reduced line voltage drop.
Your assumption that water output remains the same when voltage is reduced across the pump motor contradicts the pump affinity law:Why not post what 'affinity law' you feel I have broken?
Aren't they limited to a constant efficiency assumption or something like that (I do not feel like looking it up)?
You are correct.It is line voltage not motor voltage.But the current is also line current and not motor current.Unfortunately,motor voltages and motor currents were not displayed.
Your assumption that water output remains the same when voltage is reduced across the pump motor contradicts the pump affinity law:
Pump motor brake horse power at reduced voltage = Cube of Pump RPM at reduced voltage
Pump motor brake horse power at nominal voltage Cube of Pump RPM at nominal voltage
You must have missed the point I made in post #118.Your assumption that water output remains the same when voltage is reduced across the pump motor contradicts the pump affinity law:
Pump motor brake horse power at reduced voltage = Cube of Pump RPM at reduced voltage
Pump motor brake horse power at nominal voltage Cube of Pump RPM at nominal voltage
For the cage motors I've dealt with, slip is generally 1% or less at rated load. To check, I looked at a pumping project we did with three 4-pole machines. Speed at rated power is 1493 rpm and, like yourselves, our supply frequency is 50Hz. You will thus deduce have no difficulty in deducing that slip in this case is below 0.5%. Voltage optimisation is generally deployed when the motor is running at lower that rated load meaning that slip is even lower. To take as an example the machine I cited, going from say 3/4 to 1/1 slip would result in a speed difference of about 0.1%. That's all. From my experience, and we do a fair bit in the water industry, measuring head or flow, far less their product*, to that level of accuracy would be a challenge.If the motor is not fully loaded, reducing the voltage will not appreciably affect the motor speed. Slip will increase but by very little.
Your one line retorts are more often vague than clear.Why can't you explain a bit how I am wrong?You are either trolling, or there is a language barrier or you are just don't understand the subject.
I want that your knowledge on pumps in general and those affinity laws in particular see some improvement if possible at all.For that purpose I provide a link below especially for you.That would be great if the electric motor efficiency was constant.